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Daniel cell, the EMF of the cell can b e increased b y
A. increasing the concentration of `Zn^(2+)` ions
B. increasing the concentration of `Cu^(2+)` ions
C. increasing the concentration of `Cu^(2+)` ions
D. decreasing the concentration of `Zn^(2+)` ions.

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1 Answers

Correct Answer - B,D
The electrochemical reaction for Daniel cell is
`Zn+Cu^(2+)rarrCu+Zn^(2+)`
`E_("cell")=E_("cell")^(@)-(0.0591)/( 2)"log"([Zn^(2+)])/([Cu^(2+)])`
`=E_("cell")^(@)+(0.0591V)/(2)"log" ([ Cu^(2+)])/([Zn^(2+)])`
`E_("Cell")` can be increased by increasing `[Cu^(2+)]`
and decreasing `[Zn^(2+)]`

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