The standard Gibbs free energy change `(DeltaG^(@)" in kJ mol"^(-1))`, in a Daniel cell `(E_("cell")^(@)=1.1 V)`, when 2 moles of `Zn (s)` is oxidized
The standard Gibbs free energy change `(DeltaG^(@)" in kJ mol"^(-1))`, in a Daniel cell `(E_("cell")^(@)=1.1 V)`, when 2 moles of `Zn (s)` is oxidized at 298 K, is closest to
A. `-212.3`
B. `-106.2`
C. `-424.6`
D. `-53.1`
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Correct Answer - C
`Zn+Cu^(+2) rarr Zn^(+2)+Cu`
`2 Zn+2 Cu^(+2) rarr 2 Zn^(+2)+2 Cu`
For 2 moles of Zn, n=4
`DeltaG^(@)=-nFE_("Cell")^(@)=-4xx96500xx1.1=-424.6 kJ`
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