In a cylinder d = 40 cm, h = 56 cm, then Curved Surface Area (CSA) = ……… cm^2. A) 7040 B) 6040 C) 4040 D) 3040
In a cylinder d = 40 cm, h = 56 cm, then Curved Surface Area (CSA) = ……… cm2.
A) 7040
B) 6040
C) 4040
D) 3040
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Correct option is: A) 7040
Given that d = 40 cm
\(\therefore\) r = \(\frac d2 = \frac {40}2 = 20 \, cm\)
h = 56 cm
\(\therefore\) Curved surface area of cylinder = \(2 \pi rh\)
= 2 \(\times\) \(\frac {22}7\) \(\times\) 20 \(\times\) 56 = 44 \(\times\) 160 = 7040 \(cm^2\)
Hence, the curved surface area of cylinder is 7040 \(cm^2\)
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