The volume of a cylinder is 49,896 cm^3 and its curved surface area is 4752 sq.cm. Then its radius is ……… cm.
The volume of a cylinder is 49,896 cm3 and its curved surface area is 4752 sq.cm. Then its radius is ……… cm.
A) 12.3
B) 10
C) 21
D) 13.7
12 views
1 Answers
Correct option is: C) 21
Given that the volume of the cylinder is 49896 \(cm^3\).
\(\therefore\) \(\pi r^2h\) = 49896....(1)
And curved surface area of cylinder is 4752 \(cm^2\).
\(\therefore\) \(2 \pi rh\) = 4752...(2)
On dividing equation (1) by (2), we get
= \(\frac {\pi r^2h}{2\pi rh} = \frac {49896}{4752}\)
\(\Rightarrow\) \(\frac r2 = 10.5 = \frac {21}2\)
\(\Rightarrow\) r = \( \frac {21}2 \times 2 = 21 \, cm\)
Hence, the radius of the base of cylinder is 21 cm.
12 views
Answered