`2H_(2)+O_(2)to2H_(2)O` 2 g `H_(2)` and 1 `O_(2)` react to form `H_(2)O`
`2H_(2)+O_(2)to2H_(2)O`
2 g `H_(2)` and 1 `O_(2)` react to form `H_(2)O`
A. `3.0 g`
B. `1.125 g`
C. `4.5g`
D. `2.50 g`
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Correct Answer - B
`underset(4g)(2H_(2))+underset(32g)(O_(2))tounderset(36g)(2H_(2)O)`
Here `O_(2)` is the limiting reactant
32 g of `O_(2)` gives 36 g of water
1 g of `O_(2)` gives `(36)/(32)`g of water = 1.125 g of water
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