`B_(1)` g of an element gives `B_(2)` g of its chloride, the equivalent mass of the element is
`B_(1)` g of an element gives `B_(2)` g of its chloride, the equivalent mass of the element is
A. `(B_(1))/(B_(2)-B_(1))xx35*5`
B. `(B_(2))/(B_(2)-B_(1))xx35*5`
C. `(B_(2)-B_(1))/(B_(1))xx35*5`
D. `(B_(2)-B_(1))/(B_(2))xx35*5`
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Correct Answer - A
Mass of chlorine `= (B_(2)-B_(1))` g
`(B_(2)-B_(1))` g combines with metal `= B_(1)g`
`:.` 35.5 g combines with metal `= (35.5xxB_(1))/(B_(2)-B_(1))g`
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