A container of volume V, contains `0*28` g of `N_(2)` gas. If same volume of an unknown gas under similar conditions of temperature and pressure weigh

Question

A container of volume V, contains `0*28` g of `N_(2)` gas. If same volume of an unknown gas under similar conditions of temperature and pressure weigh

A container of volume V, contains `0*28` g of `N_(2)` gas. If same volume of an unknown gas under similar conditions of temperature and pressure weighs `0*44` g, the molecular mass of the gas is
A. `22`
B. `44`
C. `66`
D. `88`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
Ratio of the masses of equal volumes of two gases under similar conditions is the same as the ratio of their molecular masses
Thus, `(M_((G)))/(M_((N_(2)))) = (0.44)/(0.28)`
`:. M_((G)) = (0.44)/(0.28)xx28 = 44`

4 views Answered 2023-02-05 15:29