Elements A and B form two compounds `B_2A_3` and `B_2A`. If 0.05 moles of `B_2A_3` weigh 9.0 g and 0.10 mole of `B_2A` weigh 10 g, then atomic wei
Elements A and B form two compounds `B_2A_3` and `B_2A`. If 0.05 moles of `B_2A_3` weigh 9.0 g and 0.10 mole of `B_2A` weigh 10 g, then atomic weight of A and B are :-
A. 20 and 30
B. 30 and 40
C. 40 and 30
D. 30 and 20
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Correct Answer - C
0.05 mol `B_2A_3` = 9 g
1 mol `B_2A_3 = 9/0.05 `= 180 g
`therefore` 2B+3A = 180 ….(i)
0.10 mol `B_2A`=10 g
1 mol `B_2A=10/0.10`=100 g
`therefore` 2B +A = 100 ….(ii)
On solving (i) & (ii)
A = 40, B = 30
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