1.5 g of hydrocarbon on combustion in excess of oxygen produces 4.4 g of `CO_(2)` and 2.7 g of `H_(2)O`, the data illustrates

Question

1.5 g of hydrocarbon on combustion in excess of oxygen produces 4.4 g of `CO_(2)` and 2.7 g of `H_(2)O`, the data illustrates

1.5 g of hydrocarbon on combustion in excess of oxygen produces 4.4 g of `CO_(2)` and 2.7 g of `H_(2)O`, the data illustrates
A. Law of conservation of mass
B. Law of multiple proportions
C. Law of constant composition
D. Law of reciprocal proportions.

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
Mass of hydrocarbon CH = 1.5 g
changes to `CO_(2)` and H changes to `H_(2)O`
C in `4*4` g of `CO_(2) = 1*2g`
H in `2*7 g` of `H_(2)O = (2xx2*7)/(18) = 0*3g`
Mass of C + Mass of H `= 1*2 + 0*3 = 1*5g`
Which is equal to the mass of hydrocarbon taken.

5 views Answered 2023-02-05 15:29