If `K_(a)` for formic acid is `2.0 xx 10^(-4)` mol `L^(-1)` then `K_(h)` for `HCOO^(-)` is

Question

If `K_(a)` for formic acid is `2.0 xx 10^(-4)` mol `L^(-1)` then `K_(h)` for `HCOO^(-)` is

If `K_(a)` for formic acid is `2.0 xx 10^(-4)` mol `L^(-1)` then `K_(h)` for `HCOO^(-)` is
A. `2.0 xx 10^(-10)`
B. `1.414 xx 10^(-12)`
C. `10^(-13)`
D. `5 xx 10^(-11)`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
`K_(h)=(K_(w))/(K_(a))=(10^(-14))/(2.0 xx 10^(-4))`

5 views Answered 2023-02-05 15:29