Given that the food energies of `:N-=N` is kJ `"mol"^(-1)` , H-H is 435 kJ `"mol"^(-1),N-N` is 159 kJ `"mol"^(-1)`, and N-H is 389 kJ `"mol"^(-1)` , t

Question

Given that the food energies of `:N-=N` is kJ `"mol"^(-1)` , H-H is 435 kJ `"mol"^(-1),N-N` is 159 kJ `"mol"^(-1)`, and N-H is 389 kJ `"mol"^(-1)` , t

Given that the food energies of `:N-=N` is kJ `"mol"^(-1)` , H-H is 435 kJ `"mol"^(-1),N-N` is 159 kJ `"mol"^(-1)`, and N-H is 389 kJ `"mol"^(-1)` , the heat of formation of hydrazine in the phase in kJ `"mol"^(-1)` is :
A. 833
B. 101
C. 334
D. 1268

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`N_(2)+2H_(2)rarr1N_(2)H_(4)" " , DeltaH_(f)`
`DeltaH_(f)=1xxE_(N-=N)+2E_(H-H)-4E_(N-H)-1E_(N-N)`
`=[(1xx946)+(2xx435)-4xx(389)-1xx(159)]kJ`
`=101 kJ//"mol"`

5 views Answered 2023-02-05 15:29