Calculate `[H^+],[HCOO^(-)] and [OCN^(-)]` in a solution that contains 0.1 M HCOOH `(K_a=2.4xx10^(-4)) and 0.1 M HOCN (K_a=4xx10^(-4))`.

Question

Calculate `[H^+],[HCOO^(-)] and [OCN^(-)]` in a solution that contains 0.1 M HCOOH `(K_a=2.4xx10^(-4)) and 0.1 M HOCN (K_a=4xx10^(-4))`.

Calculate `[H^+],[HCOO^(-)] and [OCN^(-)]` in a solution that contains 0.1 M HCOOH `(K_a=2.4xx10^(-4)) and 0.1 M HOCN (K_a=4xx10^(-4))`.
A. `[H^+]=8xx10^(-3)M`
B. `[HCOO^(-)]=3xx10^(-3)M`
C. `[OCN^(-)]=5xx10^(-3)M`
D. All of these

Monjur Alahi

15 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
`[H^+]=sqrt((0.1xx2.4xx10^(-4))+(0.1xx4xx10^(-4)))=8xx10^(-3)M`
for HCOOH, `Ka=2.4xx10^(-4)=([H^+][HCOO^(-)])/([HCOOH])`
`:. [HCOO^(-)]=3xx10^(-3) M`
for HOCN, `Ka=4xx10^(-4)=([H^+][OCN^(-)])/([HOCN])`
`:. [OCN^(-)]=5xx10^(-3) M`

15 views Answered 2023-02-05 15:29