The pH of a solution obtained by mixing 100mL of a solution pH of `=3` with 400mL of a solution of pH `=4` is

Question

The pH of a solution obtained by mixing 100mL of a solution pH of `=3` with 400mL of a solution of pH `=4` is

The pH of a solution obtained by mixing 100mL of a solution pH of `=3` with 400mL of a solution of pH `=4` is
A. `3- log 2.8`
B. `7- log 2.8`
C. `4- log 2.8`
D. `5-log 2.8 `

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`N_(1)V_(1)+N_(2)V_(2)=N_(3)(100+400)`
or `N_(3)=(0.1+0.04)/(500)=(0.14)/(500)=2.8 xx 10^(-4)M`
`pH=-log (2.8 xx 10^(-4))=4=log 2.8`

4 views Answered 2023-02-05 15:29