Calculate the osmotic pressure of a soution obtained by mixing `100cm^(3)` of 0.25 M solution of urea and `100cm^(3)` of 0.1 M solution of cane sugar

Question

Calculate the osmotic pressure of a soution obtained by mixing `100cm^(3)` of 0.25 M solution of urea and `100cm^(3)` of 0.1 M solution of cane sugar

Calculate the osmotic pressure of a soution obtained by mixing `100cm^(3)` of 0.25 M solution of urea and `100cm^(3)` of 0.1 M solution of cane sugar at 298 K

Monjur Alahi

6 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - 4.28 atm
`"No. of moles of urea"=(0.25" mol")xx((100cm^(3)))/((1000cm^(3)))=0.025 mol`
`"No. of moes of cane sugar"=(0.1"mol")xx((100cm^(3)))/((1000cm^(3)))=0.01 mol`
`"Total no. of moles of solutes"=(0.025+0.01)=0.035 mol`
`"Total volume of the solution"=200/1000=0.2 L`
`"Osmotic pressure "(pi)=(n_(B)RT)/V=((0.035mol)xx(0.0821"L atm K"^(-1)mol^(-1))xx(298K))/((0.2L))=4.28 atm.`