Given that `Deltah_(f)(H)=218 kJ//mol`. Express the `H-H` bond energy in `K cal//mol`

Given that `Deltah_(f)(H)=218 kJ//mol`. Express the `H-H` bond energy in `K cal//mol`
A. `52.15`
B. `9.11`
C. `104`
D. `52.53`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Salim Ahmed Kawsar

Correct Answer - C
Bond energy of hydrogen
`="Enthalpy of formation"xx2`
`=218xx2=436 kJ mol^(-1)`
`=(436)/(4.184)=104.2- cal mol^(-1) [ 1 "calorie"=4.184 "joule" mol^(-1)]`

4 views Answered 2023-02-05 15:29

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