Enthalpy change of the reaction `2H(g) to H_(2)(g)` is `-104 kcal` The `H-H` bond dissociation energy is
Enthalpy change of the reaction
`2H(g) to H_(2)(g)` is `-104 kcal`
The `H-H` bond dissociation energy is
A. `104 kcal`
B. `-104 kcal`
C. `-52 kcal`
D. `+52 kcal`
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Correct Answer - A
For diatomic molecules, `BE=BDE`. Thus bond dissociation energy of `H_(2)` is `104 kcal`.
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