Enthalpy change for the reaction `2H(2)(g)rarr4H(g)` is `-869.6kJ` The dissociation energy of `H--H`bond is:
Enthalpy change for the reaction
`2H(2)(g)rarr4H(g)` is `-869.6kJ`
The dissociation energy of `H--H`bond is:
A. `+217.4 kJ`
B. `-431.8 kJ`
C. `-869.6kJ`
D. `+434.8 kJ`
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Correct Answer - B
`2H_(2)(g)to4H(g)`, `DeltaH=869.6 kJ`
or `H_(2)(g)to2H(g)`, `DeltaH=+(869.6)/(2)`
`=434.8 kJ`
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