calcaulate the bond enthalpy of Xe - F bond as given in the equation , `XeF_(4) (g) to Xe^(+)(g) + F^(-) (g) + f_(2)(g)+ F(g)` `Delta_(r)H= 292 kcal m
calcaulate the bond enthalpy of Xe - F bond as given in the equation ,
`XeF_(4) (g) to Xe^(+)(g) + F^(-) (g) + f_(2)(g)+ F(g)`
`Delta_(r)H= 292 kcal mol ^(-1)`
lonisation energy of `Xe = 279 kcal mol ^(-1)`
bond energy (F--F) = 38 kcal / mol
Electronaffinity of F = 85 kcal / mol
A. 8.5 kcal/mol
B. 34 kcal / mol
C. 24 kcal / mol
D. none of these
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Correct Answer - b
`Delta_(r)H`= heat supplied- heat evoled
`292 = (x+ 279)-(38+85) , x= 34 kcal mol^(-1)
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