The volume of water to be added to `N//2 HCI` to prepare `500 cm^(3)` of `N//10` solution is

Question

The volume of water to be added to `N//2 HCI` to prepare `500 cm^(3)` of `N//10` solution is

The volume of water to be added to `N//2 HCI` to prepare `500 cm^(3)` of `N//10` solution is
A. `45cm^(3)`
B. `400 cm^(3)`
C. `450cm^(3)`
D. `100cm^(3)`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`N_(1)V_(1) = N_(2)V_(2)`
`(N)/(2) xx V_(1) = (N)/(10) xx 500`
`V_(1) = 100`
Vol of `N//10` solution `= 500 cm^(3)`
Vol. of `N//2` solution `= 100 cm^(3)`
`:.` Water to be added `= (500 - 100) cm^(3) = 400 cm^(3)`

4 views Answered 2023-02-05 15:29