At a particular temperature, the vapour pressure of two liquids A and B are 120 and 180 mm Hg respectively. If 2 mole of A and 3 mole of B are mixed to form an ideal solution, the vapour pressure of the solution at the same temperature will be (in mm Hg)
A. 156
B. 145
C. 150
D. 108

8 views

1 Answers

Correct Answer - A
`P_("solution") = x_(A) P_(A)^(@) +x_(B) P_(B)^(@)`
`= (2)/(5) xx 120 mm +(3)/(5) xx 180 mm`
`= (1)/(5) [240 +540] mm = (780)/(5) = 156 mm`

8 views

Related Questions