In order to prepare `100cm^(3)` of `0.250M` barium chloride solution, the amount of `BaCI_(2).2H_(2)O` required will be

Question

In order to prepare `100cm^(3)` of `0.250M` barium chloride solution, the amount of `BaCI_(2).2H_(2)O` required will be

In order to prepare `100cm^(3)` of `0.250M` barium chloride solution, the amount of `BaCI_(2).2H_(2)O` required will be
A. 0.250 moles
B. .0025 moles
C. 2.5 moles
D. `6.1g` of `BaCI_(2).2H_(2)O`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
Amount of `BaCI_(2).2H_(2)O` required
`= (1"mole")/(1000) xx 100 xx 0.2` moles
`= 0.025 xx 224 = 6.1g`

5 views Answered 2023-02-05 15:29