The number of turns in the primary and secondary coils of an ideal transformer are 140 and 280, respectively. If the current through the primary coils
The number of turns in the primary and secondary coils of an ideal transformer are 140 and 280, respectively. If the current through the primary coils is 4 A, what will be the current in the secondary coil?
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In an ideal transformer, the powers of the secondary and primary coild are equal,
i.e., `V_sI_s=V_pI_p`
`therefore I_s=I_p.p/V_s=I_P.N_P/N_s=4times140/280=2A`.
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