Molar conductivity of a solutions is `1.26xx10^(2) Omega^(-1)cm^(2) "mol"^(-1)` its molarity is 0.01. its specific conductivity will be

Question

Molar conductivity of a solutions is `1.26xx10^(2) Omega^(-1)cm^(2) "mol"^(-1)` its molarity is 0.01. its specific conductivity will be

Molar conductivity of a solutions is `1.26xx10^(2) Omega^(-1)cm^(2) "mol"^(-1)` its molarity is 0.01. its specific conductivity will be
A. `1.26xx10^(-25)`
B. `1.26xx10^(-3)`
C. `1.26xx10^(-4)`
D. `0.0063`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`^^_(m)=(kxx1000)/("Molarity")"or"k=^^_(m)xx("Molarity")/(1000)`
`=(1.26xx10^(2)xx0.01)/(1000)=1.26xx10^(-3)`

4 views Answered 2023-02-05 15:29