Calculate limiting molar conductivity of `CaSO_(4)` given that limiting molar conductivity of calcium and sulphate ions are 119.0 and `160.0" S "cm^(2) mol^(-1)` respectively.

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`Lambda_(CaSO_(4))^(oo)=lambda_(Ca^(2+))^(oo)+lambda_(SO_(4)^(2-))^(oo)=(119.0+160.0)=279 " S "cm^(2) mol^(-1).`

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