The standard electrode potential of the half cells are given below. `ZnrarrZn^(2+)+2e^(-):E^(@)=0.76V` `FerarrFe^(2+)+2e^(-):E^(@)=0.44V` The emf of t

Question

The standard electrode potential of the half cells are given below. `ZnrarrZn^(2+)+2e^(-):E^(@)=0.76V` `FerarrFe^(2+)+2e^(-):E^(@)=0.44V` The emf of t

The standard electrode potential of the half cells are given below.
`ZnrarrZn^(2+)+2e^(-):E^(@)=0.76V`
`FerarrFe^(2+)+2e^(-):E^(@)=0.44V`
The emf of the cell
`Fe^(2+)+ZnrarrZn^(2+)+Fe` is
A. `-0.32V`
B. `+0.32V`
C. `+1.20V`
D. `-1.20V`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
The given electrode are oxidation potential so reduction potential are
`E_(Za)^(+2)//Zn=-0.76V`
`E_(Fe)^(@)//Fe=-0.44V`
then `E_("cell")^(@)=E_(c)^(@)-E_(a)^(@)`

4 views Answered 2023-02-05 15:29