The standard oxidation potential `E^(@)` for the half cell reactions are `Zn rarrZn^(2+)+2e^(-):E^(@)=+0.76V` `FerarrFe^(2+)+2e^(-)"E^(@)=+0.41V` EMF
The standard oxidation potential `E^(@)` for the half cell reactions are
`Zn rarrZn^(2+)+2e^(-):E^(@)=+0.76V`
`FerarrFe^(2+)+2e^(-)"E^(@)=+0.41V`
EMF of the cell reaction
`Fe^(2+)+ZnrarrZn^(2+)+Fe` will be
A. `-0.35V`
B. `+0.35V`
C. `0.17V`
D. `1.17V`
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Correct Answer - B
Emf of the cell `=E_("cathode")^(@)-E_("anode")^(@)`
`=-0.14-(-0.76)=+0.35`
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