If the standard electrode poten tial of `Cu^(2+)//Cu` electrode is 0.34V. What is the electrode potential of 0.01 M concentration of `Cu^(2+)`?

Question

If the standard electrode poten tial of `Cu^(2+)//Cu` electrode is 0.34V. What is the electrode potential of 0.01 M concentration of `Cu^(2+)`?

If the standard electrode poten tial of `Cu^(2+)//Cu` electrode is 0.34V. What is the electrode potential of 0.01 M concentration of `Cu^(2+)`?
A. 0.399V
B. 0.281V
C. 0.222V
D. 0.176V

Monjur Alahi

6 views

2025-01-04 04:42

1 Answers

Related Questions

Normal aluminium electrode coupled with normal hydrogen electrode gives an emf of 1.66 volts . So the standard electrode potential of aluminium is

2 Answers 4 Views

The electrode potential of calomel electrode , used as a reference electrode

2 Answers 4 Views

A standard hydrogen electrode has zero electrode potential is assumed to be

2 Answers 4 Views

(a). What is standard hydrogen electrode? (b). Give the reactions that occurs at this electrode wen it acts as positive in an electrochemical cell.

2 Answers 4 Views

Why is standard hydrogen electrode called reversible electrode?

2 Answers 4 Views

For the cell prepared from electrode A and B , Electrode `A : Cr_(2)O_(7)^(2-) | Cr^(3+) , E_("red")^(@) = 1.33 V` and Electrode `B : Fe^(3+) | Fe^(2+

2 Answers 5 Views

The standard electrode potential for Daniell cell is 1.1 V. Calculate the standard Gibbs energy for the reaction. `Zn(s)+Cu^(2+)(aq)rarrZn^(2+)(aq)+Cu

2 Answers 6 Views

The reduction potentials of `Cu^(2+)//Cu` and `Ag^(+)//Ag` electrodes are 0.34V and 0.80 v respectively. For what concentration of `Ag^(+)` ions will

2 Answers 4 Views

Calculate the standard electrode potential of the `Ni^(2+)//Ni` electrode , if the cell potential potential of the cell, `Ni//N^(2+)(0.01 M)//Cu is 0.

2 Answers 4 Views

For the cell prepared from electrode A and B, electrode A:`(Cr_2O_7^(2-))/(Cr^(3+)), E_("red")^(0)=+1.33V` and electrode B :`(Fe^(3+))/(Fe^(2+)), E_("

2 Answers 4 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`Cu^(2+)2e^(-)rarrCu`
`E=E^(@)-(0.0591)/(n)"log")(1)/([M^(n+)])`
`E_(cu^(2+_(//Cu)))-(0.0591)/(2)"log"(1)/(10^(2))`

6 views Answered 2023-02-05 15:29