Compelete reaction of 2.0 g calcium (at wt. = 40) with excess HCl produces 1.125 L of `H_(2)` gas. Complete reaction of the same wuantity of another m

Question

Compelete reaction of 2.0 g calcium (at wt. = 40) with excess HCl produces 1.125 L of `H_(2)` gas. Complete reaction of the same wuantity of another m

Compelete reaction of 2.0 g calcium (at wt. = 40) with excess HCl produces 1.125 L of `H_(2)` gas. Complete reaction of the same wuantity of another metal "M" with excess HCl produces 1.85 L of `H_(2)` gas under identical conditions . The equivalent weight of "M" is closest to :
A. 23
B. 9
C. 7
D. 12

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
`((eq)_(Ca))/((eq)_(M))=((eq)_(H_(2)),"released")/((eq)_(H_(2))," released")`
`((2/20))/((2/x))=((1.125)/(("eq.vol")H_(2)))/((1.85)/(("eq.vol".)H_(2)))" " {because"eq wt of M=X"}`
`:. x/20=1.125/1.85`
`x=1.125/1.85xx20~~12`

4 views Answered 2023-02-05 15:29