Complete the following :
`underset("Blood red colouration")(Fe^(3+) underset("Excess")overset(SCN^(-))to (A) underset("Excess")overset(F^(-)) to (B))`
Find the spin magnetic moment of B.

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` underset("Blood red colouration")(underset((Fe^(3+)))(FeCl_(3)) underset("Excess")overset(SCN^(-))to underset((A))(Fe(SCN)_(3)) underset("Excess")overset(F^(-)) to underset((B))([FeF_(6)]^(3-)))`
The configuration of `Fe^(3+)=[Ar]^(18)3d^(5)`
No. of unpaired electrons (n)=5.
`:.` Spin magnetic moment of B `=sqrt(n(n+2))=sqrt(5(5+2))=5.916 BM`.

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