Which of thses particles having the same kinetic energy has the largest de Broglie wavelength ?
A. Electron
B. Alpha particle
C. Proton
D. Neutron

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1 Answers

Correct Answer - A
(a) : `As" "lamda=(h)/(sqrt(2mK))" "so" "lamdaprop(1)/(sqrt(m))`
Out of the given particles m is least for electron, therefore electron has the largest value of de Broglie wavelength.

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