A particle of mass 4m at rest decays into two particles of masses m and 3m having non-zero velocities. The ratio of the de Broglie wavelengths of the particles 1 and 2 is
A. `(1)/(2)`
B. `(1)/(4)`
C. 2
D. 1

6 views

1 Answers

Correct Answer - D
(d) : According to law of conservation of linear momentum.
The de Broglie wavelength is given by
`lamda=(h)/(p)" ":." "(lamda_(1))/(lamda_(2))=1`

6 views

Related Questions