Two particles of masses 5 gm and 10 gm are 12 cm apart. What will be the location of the centre of mass of the system of these two particles from the lighter particle is ?
A. 8 cm
B. 6 cm
C. 4 cm
D. 9 cm

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1 Answers

Correct Answer - A
`r_(1)=((m_(2))/(m_(1)+m_(2)))r=(10)/(15)xx12=8 cm`

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