A single slit is illuminated by light of wavelength 6000 Ã…. The slit width is 0.1 cm and the screen is placed 1 m away. The angular position of `10^(

Question

A single slit is illuminated by light of wavelength 6000 Ã…. The slit width is 0.1 cm and the screen is placed 1 m away. The angular position of `10^(

A single slit is illuminated by light of wavelength 6000 Ã…. The slit width is 0.1 cm and the screen is placed 1 m away. The angular position of `10^(th)` minimum in radian is
A. `2 xx 10^(-4)`
B. `6 xx 10^(-3)`
C. `3 xx 10^(-3)`
D. `1 xx 10^(-4)`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Related Questions

In a double slite experiment, the distance between the slit is `0.05 cm and` screen is 2 m away from the slits. The wavelength of light is `6xx10^(-5)

2 Answers 9 Views

In a two slit experiment with monochromatic light fringes are obtained on a screen placed at some distance from the sits. If the screen is moved by m

2 Answers 4 Views

First diffraction minima due to of a single slit diffraction is at `theta = 30^(@)` for a light of wavelength `6000 Å`. The width of slits is

2 Answers 4 Views

In a single slit diffraction, the width of slit is `0.5 cm`, focal lengths of lens is 40 cm and wavelength of light is 40 cm and wavelength of light i

2 Answers 5 Views

In a biprism experiment, the slit is illuminated by a light of wavelength 5000Å . The distane between the slit and wyepieceis 1,. If the distance betw

2 Answers 5 Views

In a biprism expeirment the slit is illuminated with light of waveleght 6000Å. The distance between the slit and eye piece is `0.9`m. The virtual imag

2 Answers 5 Views

In a biprism expeirment the slit is illuminated with light of wavelength 4800Å. The distance between the slit and eyepiece is 80 cm. the sources is th

2 Answers 4 Views

In a double experiment, the distance between the slit is 1 mm and screen is 25 cm away from the slits. The wavelength of light is `6000Å`. The width o

2 Answers 6 Views

Light of wavelength 6328 Å is incident normally on a slit of width 0.2 mm. Calculate the angular width of central maximum on a screen distance 9 m?

2 Answers 4 Views

In a single slit diffraction experiment, the width of the slit is made double its original width. Then the central maximum of the diffraction pattern

2 Answers 11 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
Here, `n=10,lambda=6000 Ã…=6xx10^(-7)m,`
`d=0.1cm=10^(-3)m`
Angular position of `10^(th)` minima,
`theta=(n lambda)/(d)=(10xx6xx10^(-7))/(10^(-3))=6xx10^(-3)`rad

4 views Answered 2023-02-05 15:29