What current strength in ampere will be required to liberate 5 g of iodine from potassium iodide solution in 30 minutes ?
A. 1.11 amp
B. 2.11 amp
C. 4 amp
D. 10 amp

6 views

1 Answers

Correct Answer - B
`I^(-) to (1)/(2) I_(2) + e^(-) , (1)/(2) xx 254 `g require Q = 96500 C .
Hence 10 g will require
`Q = (96500)/(127) xx 10 = 7598.4 C `
`I = (Q)/(t) = (7594.4)/(60 xx 60) = 2.11 `A .

6 views