Given`^^^""^(@)=((1)/(3)Al^(3+))=63 cm^(2)//Omega` mol and `^^^ ""^(@)((1)/(2)SO_(4)^(2-))=80 cm^(2)//Omega mol`. The value of `^^^ ""^(@) Al_(2)(SO_(

Question

Given`^^^""^(@)=((1)/(3)Al^(3+))=63 cm^(2)//Omega` mol and `^^^ ""^(@)((1)/(2)SO_(4)^(2-))=80 cm^(2)//Omega mol`. The value of `^^^ ""^(@) Al_(2)(SO_(

Given`^^^""^(@)=((1)/(3)Al^(3+))=63 cm^(2)//Omega` mol and `^^^ ""^(@)((1)/(2)SO_(4)^(2-))=80 cm^(2)//Omega mol`.
The value of `^^^ ""^(@) Al_(2)(SO_(4))_(3)` would be
A. `143 Omega^(-1) cm^(2) mol^(-1)`
B. `206 Omega^(-1) cm^(2) mol^(-1)`
C. `286 Omega^(-1) cm^(2) mol^(-1)`
D. `858 Omega^(-1) cm^(2) mol^(-1)`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - D
`Lambda_((Al^(3+))^(@) = 3 Lambda_(((1)/(3) Al^(3+)))`
=` 3 xx 63 = 189 Omega^(-1) cm^(2) mol^(-1)` .
`Lambda^(@) (SO_(4))^(2-) = 2 Lambda^(@) ((1)/(2) SO_(4)^(2-))`
`= 2 xx 80 = 160 Omega^(-1) cm^(2) mol^(-1)` .
`Lambda^(@) [Al_(2) (SO_(4))_(3)] = 2Lambda^(@) (Al^(3+) ) + 3 Lambda^(@) (SO_(4)^(2-))`
`2 xx 189 +3 xx 160 = 858 Omega^(-1) cm^(2) mol^(-1)` .