Which one will liberate `Br_(2)` from `KBr`?
Which one will liberate `Br_(2)` from `KBr`?
A. `HI`
B. `I_(2)`
C. `Cl_(2)`
D. `SO_(2)`
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Correct Answer - C
Cl is placed above Br in electrochemical series , the non- metal placed above in series , replaces other from its solution , which is placed below of them .
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