The solution containing 4g of KBr dissolved in 100 g of water freezes at `- 1.24^(@)C.` The molar mass of KBr is `(K_(f) = 1.86 K kg "mol"^(-1)`

Question

The solution containing 4g of KBr dissolved in 100 g of water freezes at `- 1.24^(@)C.` The molar mass of KBr is `(K_(f) = 1.86 K kg "mol"^(-1)`

The solution containing 4g of KBr dissolved in 100 g of water freezes at `- 1.24^(@)C.`
The molar mass of KBr is `(K_(f) = 1.86 K kg "mol"^(-1)`
A. 102
B. 120
C. 39
D. 60

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`M_(2) = i(K_(f) xx W_(2))/(Delta T_(f) xx W_(1)) xx 1000`
`= 2 xx (1.86 xx 4)/(1.24 xx 100) xx 1000 = 120`
`M_(2) "For" KBr = 39 + 80 = 119`

4 views Answered 2023-02-05 15:29