Pure benzene freezes at `5.45^(@)C` at a certain place but a 0.374m solution of tetrachloroethane in benzene freezes at `3.55^(@)C`. The `K_(f)` for benzene is
A. 5.08 K kg `"mol"^(-1)`
B. 508 K kg `"mol"^(-1)`
C. 0.508 K kg `"mol"^(-1)`
D. `50.8^(@) C `kg `"mol"^(-1)`

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Correct Answer - A
`K_(f) = Delta T_(f) // m = (5.45 - 3.55) // 0.374`
`= 5.08 K kg "mol"^(-1)`

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