In a solution of 7.8 g benzene `(C_(6)H_(6))` and 46.0 g toluene `(C_(6)H_(5)CH_(3))` the mole fraction of benzene is :

Question

In a solution of 7.8 g benzene `(C_(6)H_(6))` and 46.0 g toluene `(C_(6)H_(5)CH_(3))` the mole fraction of benzene is :

In a solution of 7.8 g benzene `(C_(6)H_(6))` and 46.0 g toluene `(C_(6)H_(5)CH_(3))` the mole fraction of benzene is :
A. `1//6`
B. `1//5`
C. `1//2`
D. `1//3`

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
Mole fraction of `C_(6)H_(6)=(7.8//78)/(7.8/78+46/92)=1/6`

5 views Answered 2023-02-05 15:29