One mole of acidified `K_(2)Cr_(2)O_(7)` in reaction with excess `KI` will liberate …… moles of `I_(2)`
One mole of acidified `K_(2)Cr_(2)O_(7)` in reaction with excess `KI` will liberate …… moles of `I_(2)`
A. 6
B. 1
C. 7
D. 3
4 views
1 Answers
Correct Answer - D
`Cr_(2)O_(7)^(2-)+14H^(+)+6I^(-)rarr2Cr^(3+)+7H_(2)O+3I_(2)`
3 moles of `I_(2)` per mole of `K_(2)Cr_(2)O_(7)` are produced.
4 views
Answered