For `2NO+O_(2)to 2NO_(2)` change if the volume of the reaction vessel is doubled , the rate of the reaction
For `2NO+O_(2)to 2NO_(2)` change if the volume of the reaction vessel is doubled , the rate of the reaction
A. Will diminsh to 1/4 of initial value
B. Will diminsh to 1/8 of initial value
C. Will grow 4 times
D. will grow 8 times
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Correct Answer - B
Volume is doubled therefore concentration become half .
Reaction is 3d order ` therefore ((1)/(2))^(3) =(1)/(8)`
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