The magnet potential at a point on the line inclined at `60^(@)` with the axis of short magnet is `1.5 xx 10^(-5) J//Am`.If the magnetic moment of mag
The magnet potential at a point on the line inclined at `60^(@)` with the axis of short magnet is `1.5 xx 10^(-5) J//Am`.If the magnetic moment of magnet is `3Am^(2)`,then the distance of the point from the centre of the dipole will bw
A. 0.1m
B. 0.1 cm
C. 0.01 m
D. 0.5 m
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Correct Answer - A
`r^(2)=(mu_(0))/(4pi)M[(1)/(r_(1)^(2))-(1)/(r_(2)^(2))]=10^(-7)xx3[(1)/(0.25)-(1)/(1)]`
`=9xx10^(-7)J//Am`
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