The magnetic potential at a point on the line inclined at `30^(@)` with the axis of a short magnet is `1.5xx10^(-5) J//Am`If the magnetic moment is `1

Question

The magnetic potential at a point on the line inclined at `30^(@)` with the axis of a short magnet is `1.5xx10^(-5) J//Am`If the magnetic moment is `1

The magnetic potential at a point on the line inclined at `30^(@)` with the axis of a short magnet is `1.5xx10^(-5) J//Am`If the magnetic moment is `1.732 Am^(2)`,What will be distance of point from centre of the magnet?
A. 10cm
B. 1 cm
C. 0.1 cm
D. 0.001cm

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`V=(mu_(0))/(4pi) (Mcostheta)/(V)`
`therefore r^(2)=(mu_(0))/(4pi)(Mcostheta)/(V)`
`r^(2)=(mu_(0))/(4pi)(Mcostheta)/(V)`
`r^(2)=(4pixx10^(-7)xx1.732xxcos30)/(4pixx1.5xx10^(-5))`
`=`0.9999xx10^(-2)`
`therefore r=0.09999m 10 cm`

4 views Answered 2023-02-05 15:29