A capacitor of capacitance `1 mu F` is charged to a potential of 20 volt. The battery is then disconnected and a pure inductive coil of inductance 10

Question

A capacitor of capacitance `1 mu F` is charged to a potential of 20 volt. The battery is then disconnected and a pure inductive coil of inductance 10

A capacitor of capacitance `1 mu F` is charged to a potential of 20 volt. The battery is then disconnected and a pure inductive coil of inductance 10 mH is connected across the capacitor so that L-C oscillation are set-up in the circuit. What is the maximum current in the circuit?
A. 0.1 A
B. 0.15 A
C. 0.2 A
D. 0.3 A

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
Maximum electric energy in the capacitor
= maximum magnetic energy in the inductor
`:. 1/2 CV^(2) = 1/2 LI_(0)^(2)`
`:. I_(0)^(2) = (CV^2)/(L) :. I_(0) = sqrt(C/L)V`
`:. I_(0) = 20 xx sqrt((10^(-6))/(10xx10^(-3))) = 20 xx sqrt(10^(-4))`
`:. I_(0) = 20 xx 10^(-2) = 0.2 A`.

4 views Answered 2023-02-05 15:29