A capacitor of capacitance `10muF` charged to 100V is connected to an uncharged capacitor. The effective potential now is 40 V. The capacitance on uncharged capacitor is
A. `12muF`
B. `15muF`
C. `25muF`
D. `30muF`

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1 Answers

Correct Answer - B
Common potential of system
`V=(C_(1)V_(1)+C_(2)CV_(2))/(C_(1)+C_(2))rArr 40=(10xx100+C_(2)xx0)/(10+C_(2))`
`"or "40(10+C_(2))=1000 rArr C_(2)=15muF`

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