A condenser of capacitance `6muF` was originally charged to 10 V. Now potential difference is made 20 V. The increase in potential energy is
A condenser of capacitance `6muF` was originally charged to 10 V. Now potential difference is made 20 V. The increase in potential energy is
A. `2xx10^(-4)J`
B. `3xx10^(-4)J`
C. `6xx10^(-4)J`
D. `9xx10^(-4)J`
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Correct Answer - D
`deltaE=1/2CV_(2)^(2)-1/2CV_(1)^(2)`
`=C/2(V_(2)^(2)-V_(1)^(2))`
`=(6xx10^(-6))/2(400-100)`
`=9xx10^(-4)J`
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