When an alternating voltage of 100V, 50 Hz is applied to a choke coil, it takes a current of 10 A and the power is 500 W. What is the choke coil?

Question

When an alternating voltage of 100V, 50 Hz is applied to a choke coil, it takes a current of 10 A and the power is 500 W. What is the choke coil?

When an alternating voltage of 100V, 50 Hz is applied to a choke coil, it takes a current of 10 A and the power is 500 W. What is the choke coil?
A. `5sqrt(3) Omega`
B. `4sqrt(3) Omega`
C. `3 Omega`
D. `3sqrt(3) Omega`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
`Z = 100/10 = 10 Omega`
`P = I^(2)R :. R = )/(I_2) = 500/100 = 5 Omega`
`:. Z^(2) = R^(2) + X_(L)^(2)`
`:. X_(L) = sqrt(Z^(2)-R^(2))= sqrt(100 - 25) = sqrt(75) = 5sqrt(3) Omega`.

4 views Answered 2023-02-05 15:29