The peak value of an alternating e.m.f. is 141.4 V. What would be the reading of an a.c. voltmeter when connected across this e.m.f. ?
A. a. 100 V
B. b. 141.1 V
C. c. 220 V
D. d. zero

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1 Answers

Correct Answer - A
`e_(rms) = (e_0)/(sqrt(2)) = (141.4)/(1.414) 100 V`

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