The current in a coil changes from 0 to 2 A in 0.05 sec. If the induced e.m.f is 80 V, the self inductance of the coil is
A. 2.4 H
B. 2 H
C. 1.5 H
D. 1 H

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1 Answers

Correct Answer - B
`e = L(dI)/(dt) :. L = e(dt)/(dI) = (80 xx 5 xx 10^(-2))/(2) = 2 H`.

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