If A is the area of each plate, charge on it is q and potential difference is V then the distance between the parallel plate capacitor is

Question

If A is the area of each plate, charge on it is q and potential difference is V then the distance between the parallel plate capacitor is

If A is the area of each plate, charge on it is q and potential difference is V then the distance between the parallel plate capacitor is
A. `(epsi_(0)AV)/(2q)`
B. `(epsi_(0)AV)/(q)`
C. `(2epsi_(0)AV)/(q)`
D. `(AV)/(q)`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`V=E*d`
`d=V/E=V/(sigma/epsi_(0))`
`=(V/q)/(Aepsi_(0))=(VAepsi_(0))/q`

4 views Answered 2023-02-05 15:29